Math, asked by manjotk9495, 14 days ago

Subtract:4p2q-3q+5pq2-8p+7q-10 from 18 -3p-11q-11q+5p2+5p2q

Answers

Answered by moongupta1005
1

Answer:

28 + 5p - 26q + 5p² + p²q - 5pq²

Step-by-step explanation:

(18 - 3p - 11q - 11q + 5p² + 5p²q) - (4p²q - 3q + 5pq² - 8p + 7q - 10)

First we will simplify the content in the two brackets

1) 18 - 3p - 11q - 11q + 5p² + 5p²q

= 18 - 3P -22q + 5p² + 5p²q

2) 4p²q - 3q + 5pq² - 8p + 7q - 10

= 4p²q  + 4q + 5pq² - 8p  - 10

Subtracting 2 from 1

(18 - 3P -22q + 5p² + 5p²q) - (4p²q  + 4q + 5pq² - 8p  - 10)

= 18 - 3p -22q + 5p² + 5p²q - 4p²q  - 4q - 5pq² + 8p + 10

= 28 + 5p - 26q + 5p² + p²q - 5pq²

Hope it helps

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