Subtract 4pq(p-q) from 3pq(p+q)
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Answer:
Step-by-step explanation:
= 4pq(p+q)-{3pq(p-q)}
=4p(square)q+4pq(square)-3pq(p+q)
=4p(square)q+4pq(square)-3p(square)q-3pq(square)
=4p(square)q-3p(square)q+4pq(square)-3pq(square)
= 1p(square)q+1pq(square)
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