Subtract 4x^2-3x+5 from 7\ +5x^2-3x ( The expressions are given clearly below)
Answers
Given data:
4x² - 3x + 5 and 7 + 5x² - 3x.
To Solve:
Subtract 4x² - 3x + 5 from 7 + 5x² - 3x.
Step-by-step explanation:
→ (4x² - 3x + 5) - (7 + 5x² - 3x)
→ 4x² - 3x + 5 - (5x² - 3x + 7)
→ 4x² - 3x + 5 - 5x² + 3x - 7
→ 4x² - 5x² - 3x + 5 + 3x - 7
→ 4x² - 5x² - 3x + 3x + 5 - 7
→ (4 - 5)x² + (-3 + 3)x + (5 - 7)
→ -x² + 0 + (-2)
→ -x² - 2
Hence, the subtraction of 4x² - 3x + 5 from 7 + 5x² - 3x is -x² - 2.
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- x² + 2
Step-by-step explanation:
Given :-
To subtract 4x² - 3x + 5 from 7 + 5x² - 3x.
We know that, we must include from value first,
→ 7 + 5x² - 3x - 4x² - 3x + 5
Rearranging it in correct order,
→ 5x² - 3x + 7 - (4x² - 3x + 5)
Multiplying (-) sign inside the bracket,
→ 5x² - 3x + 7 - 4x² + 3x - 5
Subtracting both we get,
→ x² + 2
More steps :-
→ 5x² - 3x + 7 - 4x² + 3x - 5
Grouping,
→ (5x² - 4x²) (-3x + 3x) (7 - 5)
Subtracting,
→ (x²) (0) (2)
→ x² + 2
- Hence, subtracting 4x² - 3x + 5 from 7 + 5x² - 3x gives x² + 2.