CBSE BOARD XII, asked by KanjoosAunty, 4 days ago

Subtract 4x^2-3x+5 from 7\ +5x^2-3x ( The expressions are given clearly below)​

Answers

Answered by sagacioux
2

Given :

  • 4x² - 3x + 5 and 7 + 5x² - 3x.

To Solve:

  • Subtract 4x² - 3x + 5 from 7 + 5x² - 3x.

Solution:

→ (4x² - 3x + 5) - (7 + 5x² - 3x)

→ 4x² - 3x + 5 - (5x² - 3x + 7)

→ 4x² - 3x + 5 - 5x² + 3x - 7

→ 4x² - 5x² - 3x + 5 + 3x - 7

→ 4x² - 5x² - 3x + 3x + 5 - 7

→ (4 - 5)x² + (-3 + 3)x + (5 - 7)

→ -x² + 0 + (-2)

→ -x² - 2

Hence, the subtraction of 4x² - 3x + 5 from 7 + 5x² - 3x is -x² - 2.

Hence, the subtraction of 4x² - 3x + 5 from 7 + 5x² - 3x is -x² - 2.

Answered by missHongkong
0

Subtract 4x^2-3x+5 from 7\ +5x^2-3x ( The expressions are given clearly below)

Given data:

4x² - 3x + 5 and 7 + 5x² - 3x.

To Solve:

Subtract 4x² - 3x + 5 from 7 + 5x² - 3x.

Step-by-step explanation:

→ (4x² - 3x + 5) - (7 + 5x² - 3x)

→ 4x² - 3x + 5 - (5x² - 3x + 7)

→ 4x² - 3x + 5 - 5x² + 3x - 7

→ 4x² - 5x² - 3x + 5 + 3x - 7

→ 4x² - 5x² - 3x + 3x + 5 - 7

→ (4 - 5)x² + (-3 + 3)x + (5 - 7)

→ -x² + 0 + (-2)

→ -x² - 2

Hence, the subtraction of 4x² - 3x + 5 from 7 + 5x² - 3x is -x² - 2.

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