Question

Subtract 4x 2 − z 2 from the sum of 2x 2 + 3y 2 − 4z 2 and x 2 − 2y 2 + z 2

Answer 1

(4x^2-z^2)-{(2x^2+3y^2-4z^2)(x^2- 2y^2+ z^2)}

(4x^2-z^2)-(3x^2+y^2-3z^2)

4x^2-z^2-3x^2-y^2+3z^2

4x^2-3x^2-y^2-z^2+3z^2

x^2-y^2+2z^2

Hope its helpful