Subtract 4x - y - 12 from the sum of 5x - 2y + 10 and x - 3y - 9
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Answer:
5x-2y+10+x-3y-9=6x-5y+1
6x-5y+1-(4x-y-12)
=(6x-4x)-5y+y+1+12
=2x-4y+13
Answered by
0
Answer:
2x - 4y + 13
Step-by-step explanation:
sum of 5x - 2y + 10 and x - 3y - 9
(5x- 2y + 10) + (x - 3y - 9)
=5x - 2y+ 10 + x - 3y- 9
=5x + x - 2y- 3y +10 - 9
=6x - 5y + 1
subtract 4x - y - 12 from 6x - 5y + 1
(6x - 5y + 1) - (4x - y -12)
=6x - 5y + 1 - 4x + y + 12
=6x - 4x - 5y + y + 1 + 12
=2x - 4y + 13
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