Question

Subtract 4y(2x+y+z) from 3x(x+y-z) ....................plz solve this sum with full steps and correct method and plz don't spam

Answer 1

Answer:

4y(2x+y+z)−3x(x+y+z)

(8xy + 4 {y}^{2} + 4yz) - (3 {x}^{2} + 3xy - 3x

(8xy+4y 2 +4yz)−(3x 2+3xy−3xz)

(8xy + 3xy) + (4 {y}^{2} + 3 {x}^{2} ) - (4yz - 3xz)(8xy+3xy)+(4y 2 +3x 2 )−(4yz−3xz)

(11 {x}^{2} {y}^{2} ) + (7 {x}^{2} {y}^{2} ) - (1xy)(11x 2y+(7x 2y 2)−(1xy)

(18 {x}^{4} {y}^{4} ) - (1xy)(18x 4 y 4 )−(1xy)

(18 {x}^{4} {y}^{4} - 1xy)(18x 4 y 4 −1xy)

17 {x}^{3} {y}^{3}17x 3 y