Subtract 5a(b+c-4a) – 2b( a-b+c) from 4a(2a-7b+4c)
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Answer:
Step-by-step explanation:
First find the sum of all terms
\begin{gathered}a + 3b - 4c \\ \\ 4a - b + 9c \\ \\ - a - 2b + 3c \\ \\ sum \: of \: all \: terms = \\ a + 4a - a + 3b - b - 2b - 4c + 9c + 3c \\ \\ = 4a + 8c \\ \\ \end{gathered}
a+3b−4c
4a−b+9c
−a−2b+3c
sumofallterms=
a+4a−a+3b−b−2b−4c+9c+3c
=4a+8c
Now subtract
\begin{gathered} = 4a + 8c - (2a - 3b + 4c) \\ \\ = 4a - 2a + 3b + 8c - 4c \\ \\ = 2a + 3b + 4c \\ \\ \end{gathered}
=4a+8c−(2a−3b+4c)
=4a−2a+3b+8c−4c
=2a+3b+4c
Hope it helps you.
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