Subtract -5a square -3a+1 from the sum of 4a square +3-8a and 9a-7
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Answers
Answer:
your answer is 9a square +4a -5
Step-by-step explanation:
step 1 : first, you have to add (4a square +3 -8a) with (9a -7)
(4a square +3 -8a) + (9a -7) = (4a square +a -4)
step 2 : next, subtract (-5a square -3a +1) from (4a square +a -4), i.e., (4a square +a -4) - (-5a square -3a +1) = (9a square +4a. -5)
Remember : You have to change the symbols of the second equation (i.e., (-5a square -3a +1)) while subtracting, But while you are adding, you should keep the symbols as it is. If you don't change the symbol while subtracting, your answer will be wrong.
I hope it helped you. Thank yo
Question :
Subtract -5a²-3a+1 from the sum of 4a² +3-8a and 9a-7
Answer :
9a² + 4a - 5
Step-by-step explanation :
⇒ Sum of 4a² +3-8a and 9a-7
= 4a² + 3 - 8a + 9a - 7
= 4a² + 9a - 8a + 3 - 7
= 4a² + a - 4
⇒ Subtract -5a² -3a+1 from the sum of 4a² +3-8a and 9a-7
= 4a² + a - 4 - (-5a² -3a+1)
= 4a² + a - 4 + 5a² + 3a - 1
= 4a² + 5a² + a + 3a - 4 - 1
= 9a² + 4a - 5
║ The final answer = 9a² + 4a - 5