Math, asked by asmi3331, 1 year ago

Subtract-5a square-3a+1 from the sumof 4a square+3-8a and 9a-7

Answers

Answered by rajniagrawal843
6

Answer:

Here is the answer.

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Answered by Anonymous
0

Answer:

Sum of 4a2 + 3 – 8a and 9a – 7

= 4a2 + 3 – 8a + 9a – 7 = 4a2 + a – 4

∴ (4a2 + a – 4) – (-5a2 – 3a + 1)

= 4a2 + a – 4 + 5a2 + 3a – 1

= 4a2 + 5a2 + a + 3a – 4 – 1

= 9a2 + 4a – 5

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