Subtract-5a square-3a+1 from the sumof 4a square+3-8a and 9a-7
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Sum of 4a2 + 3 – 8a and 9a – 7
= 4a2 + 3 – 8a + 9a – 7 = 4a2 + a – 4
∴ (4a2 + a – 4) – (-5a2 – 3a + 1)
= 4a2 + a – 4 + 5a2 + 3a – 1
= 4a2 + 5a2 + a + 3a – 4 – 1
= 9a2 + 4a – 5
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