Math, asked by adi643966, 5 months ago

subtract 5a³+4a²b+7ab from 4a²b+5ab+9​

Answers

Answered by iqrasadafnaaz
1

= 5a^3 + 4a^2b + 7ab - (4a^2b+5ab+9)

= 5a^3 + 4a^2b + 7ab - 4a^2b- 5ab - 9

=5a^3 + (4a^2b-4a^2b) + (7ab -5ab) - 9

= 5a^3 + (0) + (2ab) - 9

= 5a^3 + 2ab - 9

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