Math, asked by navyasree2312, 9 months ago

subtract 5ab (3a-2b-7) from 3ab(-4a+3b-8)

Answers

Answered by zahaansajid
2

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Here's your answer

3ab(-4a+3b-8) = -12a²b+9ab²-24ab

5ab(3a-2b-7) = 15a²b-10ab²-35ab

Hence,

5ab(3a-2b-7) - 3ab(-4a+3b-8)

= (15a²b-10ab²-35ab) - (-12a²b+9ab²-24ab)

= 15a²b - 10ab² -35ab + 12a²b - 9ab² + 24ab

= 27a²b - 19ab² - 11ab

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Answered by karanmanais
1

Answer:

5ab(3a-2b-7)

=15a²b-10ab²-35ab

3ab(-4a+3b-8)

= -12a²b+9ab²-24ab

(-12a²b+9ab²-24ab)-(15a²b-10ab²-35ab)

= -12a²b+9ab²-24ab-15a²b+10ab²+35ab

= -27a²b+19ab²+11ab

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