Math, asked by yashodasurabhi, 4 months ago

subtract 5ab + 3bc - 11ca from 9ab - 3bc - 11ca + 21abc

Answers

Answered by Cive

2

Answer:

9ab - 3bc - 11ca + 21abc - (5ab +3bc -11ca)

= 9ab -3bc -11ca + 21abc -5ab -3bc +11ca

= 4ab -6bc + 21abc

Answered by prachi200649

1

Answer:

4ab - 6ab

Step-by-step explanation:

(9ab - 3bc - 11ca + 21abc) - (5ab + 3bc - 11ca)

= 9ab - 3bc - 11ca + 21abc - 5ab -3bc + 11ca

= 9ab - 5ab - 3bc - 3bc - 11ca + 11ca

= 4ab - 6ab

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