Math, asked by yashodasurabhi, 4 months ago

subtract 5ab + 3bc - 11ca from 9ab - 3bc - 11ca + 21abc

Answers

Answered by Cive

2

Answer:

9ab - 3bc - 11ca + 21abc - (5ab +3bc -11ca)

= 9ab -3bc -11ca + 21abc -5ab -3bc +11ca

= 4ab -6bc + 21abc

Answered by prachi200649

1

Answer:

4ab - 6ab

Step-by-step explanation:

(9ab - 3bc - 11ca + 21abc) - (5ab + 3bc - 11ca)

= 9ab - 3bc - 11ca + 21abc - 5ab -3bc + 11ca

= 9ab - 5ab - 3bc - 3bc - 11ca + 11ca

= 4ab - 6ab

hope this helps you

plz follow me and mark as brainliest

Previous Question

Next Question

Similar questions

Math, 2 months ago

find the rational number between 3/4 and 7/8...

Math, 2 months ago

now calculate the area of the triangle 3.5 cm and 5 cm...

History, 2 months ago

Which of these is not a good reason to say that Indian elections are democratic? 1) India’s Election Commission is very powerful. 2) In India, everyone above the age of 18 has a right to vote. 3) India has the largest number of voters in the world. 4) In India, the losing parties accept the electoral verdict.

Physics, 4 months ago

can 0.32 x 10's reside in a body...

English, 4 months ago

states related to dance:- 1.andhra pradesh 2.punjab 3.karnataka 4.kerala 5.orrissa 6.tamil nadu say in which state performs which dance. NO SMAP❌...

Math, 10 months ago

the sum of the numerator and denominator of a fraction is 12 if 1 is added to both the numerator and denominator the fraction becomes 3 upon 4 find the fraction ...

Science, 10 months ago

explain the mendel's monohybrid phrenology with the help of anyone cross...

Social Sciences, 10 months ago

what is the importance of Human resources...