Question

Subtract 5x²-3xy y² - 6 from the sum of 3x²- 8xy 7 and -5x² 7xy - 3y² - 4.​

Answer 1

Correct Question:

Subtract $5x^2-3xy+ y^2 - 6$ from the sum of $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$

Final Answer:

The difference between the sum of the two algebraic expressions $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$ and the other algebraic expression $5x^2-3xy+ y^2 - 6$ is $-7x^2+2xy-4y^2+9$.

Given:

The three algebraic expressions are  $5x^2-3xy+ y^2 - 6$, $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$

To Find:

The difference between the sum of the two algebraic expressions $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$ and the other algebraic expression $5x^2-3xy+ y^2 - 6$.

Explanation:

An algebraic expression is a mathematical expression containing the mathematical operations of the algebraic variables, namely $x,y,z$ etc.

First, find the sum of the two algebraic expressions $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$ and then subtract it from the third algebraic expression $5x^2-3xy+ y^2 - 6$ to arrive at the answer.

Step 1 of 2

The sum of the two algebraic expressions $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$ is

$=(3x^2- 8xy+ 7)+(-5x^2+ 7xy - 3y^2 - 4)\\=3x^2- 8xy+ 7-5x^2+ 7xy - 3y^2 - 4\\=(3x^2-5x^2)+(- 8xy+ 7xy) - 3y^2+(7- 4)\\=-2x^2-xy - 3y^2+3$

Step 2 of 2

Now, on subtracting the algebraic expression $5x^2-3xy+ y^2 - 6$ from the above sum, the difference is

$=(-2x^2-xy - 3y^2+3)-(5x^2-3xy+ y^2 - 6)\\=-2x^2-xy - 3y^2+3-5x^2+3xy-y^2+6\\=(-2x^2-5x^2)+(-xy+3xy)+(-3y^2-y^2)+(3+6)\\=-7x^2+2xy-4y^2+9$.

Therefore, the required difference when the algebraic expression$5x^2-3xy+ y^2 - 6$ is subtracted from the sum of the two algebraic expressions $3x^2- 8xy+ 7$ and $-5x^2+ 7xy - 3y^2 - 4$ is $-7x^2+2xy-4y^2+9$.

Know more from the following links.

https://brainly.in/question/16766451

https://brainly.in/question/4211888

#SPJ1