Subtract 5x2 – 6y2 + 8y – 5 from 7x2 – 5xy + 10y2 + 5x – 4y.
tnwramit1:
is the x²
Answers
Answered by
123
I think it is 5x² so I m taking these terms like this (I.e. 5x2=5x²,6y2=6y²)
So here is ur solution
5x²-6y²+8y-5 - - - - - (1)
7x²+10y²+5x-4y-5xy------(2)
Subtracting equ(1) from equ (2), we get
7X²+10y²+5x-4y-5xy-(5x²-6y²+8y-5)
7x²+10y²+5x-4y-5xy-5x²+6y²+8y-5
2x²+16y²+5x+4y-5xy-5
This is ur ans hope it will help you in case of any doubt comment below
So here is ur solution
5x²-6y²+8y-5 - - - - - (1)
7x²+10y²+5x-4y-5xy------(2)
Subtracting equ(1) from equ (2), we get
7X²+10y²+5x-4y-5xy-(5x²-6y²+8y-5)
7x²+10y²+5x-4y-5xy-5x²+6y²+8y-5
2x²+16y²+5x+4y-5xy-5
This is ur ans hope it will help you in case of any doubt comment below
Answered by
52
The answer is
7x^2-5xy+10y^2+5x-4y - (5x^2-6y^2+8y-5)
7x^2-5xy+10y^2+5x-4y-5x^2+6y^2-8y+5 (the signs are changed when we open the bracket)
7x^2-5x^2-5xy+10y^2+6y^2+5x-4y-8y(we place all the like terms together)
This, the ans. is
2x^2-5xy+16y^2+5x-12y+5
Similar questions