Math, asked by Anonymous, 1 year ago

  Subtract 5x2 – 6y2 + 8y – 5 from 7x2 – 5xy + 10y2 + 5x – 4y. 


tnwramit1: is the x²
tnwramit1: or y²

Answers

Answered by tnwramit1
123
I think it is 5x² so I m taking these terms like this (I.e. 5x2=5x²,6y2=6y²)

So here is ur solution

5x²-6y²+8y-5 - - - - - (1)

7x²+10y²+5x-4y-5xy------(2)

Subtracting equ(1) from equ (2), we get

7X²+10y²+5x-4y-5xy-(5x²-6y²+8y-5)

7x²+10y²+5x-4y-5xy-5x²+6y²+8y-5

2x²+16y²+5x+4y-5xy-5

This is ur ans hope it will help you in case of any doubt comment below
Answered by aadyamittal2911
52

The answer is

7x^2-5xy+10y^2+5x-4y - (5x^2-6y^2+8y-5)

7x^2-5xy+10y^2+5x-4y-5x^2+6y^2-8y+5 (the signs are changed when we open the bracket)

7x^2-5x^2-5xy+10y^2+6y^2+5x-4y-8y(we place all the like terms together)

This, the ans. is

2x^2-5xy+16y^2+5x-12y+5

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