Question

Subtract 5x²+9y²-3z² from the sum of 6x²-5y² and y²+5z²

Answer 1

Step-by-step explanation:

$sum \: of \: {6x}^{2} - {5y}^{2} and \: {y}^{2} + {5z}^{2} \\ = {6x}^{2} - {5y}^{2} + {y}^{2} + {5z}^{2} \\ = {6x}^{2} - {4y}^{2} + {5z}^{2} \\ = subtracting \: {5x}^{2} + {9y}^{2} - {3z}^{2} from {6x}^{2} - {4y}^{2} + {5z}^{2} \\ = {6x}^{2} - {4y}^{2} + {5z}^{2} - ({5x}^{2} + {9y}^{2} - {3z}^{2} ) \\ = {6x -}^{2} - {4y}^{2} + {5z}^{2} - {5x}^{2} - {9y}^{2} + {3z}^{2} \\ = {6x}^{2} - {5x}^{2} - {4y}^{2} - {9y}^{2} + {5z}^{2} + {3z}^{2} \\ = {x}^{2} - {13y}^{2} + {8z}^{2}$