Math, asked by Myin8917, 7 months ago

Subtract 6 x power 2 + 7 x minus 5 from the sum of minus 2 x power 2 + 3 X + 6 and 4 x power 2 + 3x - 2

Answers

Answered by priyanshiy20008
2

Step-by-step explanation:

sum(3x2−5x+8)+(−6x2+7)3x2−5x+8−6x2+73x2−6x2−5x+8+7−3x2−5x+15difference(−3x2−5x+15)−(−9x−1)−3x2−5x+15−9x+1−3x2−5x−9x+15+1−3x2−14x+16

sum(3x2−5x+8)+(−6x2+7)3x2−5x+8−6x2+73x2−6x2−5x+8+7−3x2−5x+15difference(−3x2−5x+15)−(−9x−1)−3x2−5x+15−9x+1−3x2−5x−9x+15+1−3x2−14x+16Hope it helps you

Answered by rakshita46
2

Answer:

  1. SUM OF NO.

-2x square + 3x + 6 +4x square + 3x -2

2x square + 6x + 4

2. Now difer. the no. s

2x square +6x + 4 - (6x square + 7x - 5 )

2x square + 6x + 4 - 6x square - 7x + 5

- 3x square - x + 9 ANS

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