Question

Subtract (6a+3) from a³-3a²+4a+1.​

Answer 1

a^3 -3a^2 +4a + 1-6a-3

= a^3-3a^2-2a-2

Answer 2

Answer:

$a^{3}-3a^{2}-2a-2$

Step-by-step explanation:

The question is:

$a^{3}-3a^{2}+4a+1-(6a+3)$

Opening the brackets,

$a^{3}-3a^{2}+4a+1-6a-3$

Rearranging terms,

$a^{3}-3a^{2}+4a-6a+1-3$

So the answer comes to,

$a^{3}-3a^{2}-2a-2$