Question

Subtract 6a(a−2) from 15a^2 and then add it to a(3+7a)?

Answer 1

Step-by-step explanation:

6a(a-2)=6a^2-12a

15a^2-(6a^2-12a)

=15a^2-6a^2+12a

=9a^2+12a

9a^2+12a+a(3+7a)

=9a^2+12a+3a+7a^2

=16a^2+15a

Answer 2

Answer:

16a^2 + 15a

Step-by-step explanation:

Simplify

6a ( a- 2) = 6a^2 - 12a

Now subtract,

15a^2 - ( 6a^2 - 12a )

=> 15a^2 - 6a^2 +12a

=> 9a^2 + 12a

Add,

9a^2 + 12a + a (3 + 7a)

=> 9a^2 + 12a + 3a + 7a^2

=> 16a^2 + 15a