Math, asked by hariniprakash2004, 7 months ago

subtract 6a(a+b+c) from 3ab (-a+b+c)

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Answered by REDPLANET

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Answer:

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6a (a+b+c) = 6a² + 6ab + 6ac

3ab (-a+b+c) = -3a²b + 3ab² + 3abc

Subtract 6a(a+b+c) from 3ab (-a+b+c)

= -3a²b + 3ab² + 3abc - (6a² + 6ab + 6ac)

= -3a²b + 3ab² + 3abc - 6a² - 6ab - 6ac)

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