Question

Subtract 6x3 - 5x2 + 4x - 3 from the sum of x + 2x2 – 3x and 2 - x2 + 6x - 3​

Answer 1

Step-by-step explanation:

${:}\longrightarrow$

$(x + {2x}^{2} - 3x + 2 - {x}^{2} + 6x - 3) - ( {6x}^{3} - {5x}^{2} + 4x - 3) \\ = ({2x}^{2} - {x}^{2} + x - 3x + 6x + 2 - 3) - ( {6x}^{3} - {5x}^{2} + 4x - 3 )\\ = ( {x}^{2} - 2x + 6x - 1) - ( {6x}^{3} - {5x}^{2} + 4x - 3) \\ = {x}^{2} + 4x - 1 - ( {6x}^{3} - {5x}^{2} + 4x - 3 )\\ = {x}^{2} + 4x - 1 - {6x}^{ 3 } + {5x}^{2} - 4x + 3 \\ = - {6x}^{3} + {x}^{2} + {5x}^{2} + 4x - 4x - 1 + 3 \\ = - {6x}^{3 } + {6x}^{2} + 2$