Subtract: 7a³b-4a²b²+9 from 3a³b+2a²b²+7 proper solution
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Answer:
(12a−9ab+5b−3)−(4a−7ab+3b+12)
=(12a−4a)+(−9ab+7ab)+(5b−3b)+(−3−12)
=8a−2ab+2b−15
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Hey mate refer to the attachment oki,✌✌✌✌✌✌
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