Math, asked by Anonymous, 8 months ago

Subtract 7z(3 + y) from the product of 10y(z - 5) and 5yz.​

Answers

Answered by TeddyKayalvizhi
5

Answer:

50y^2 z^2 - 250y^2 z - 21z + 7yz

Step-by-step explanation:

10y(z - 5) * 5yz​ = (10yz - 50y) *  5yz

                         =50y^2 z^2 - 250y^2 z

7z(3 + y) = 21z + 7yz

10y(z - 5) * 5yz - 7z(3 + y) = 50y^2 z^2 - 250y^2 z - 21z + 7yz

                                       

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