Math, asked by Anonymous, 10 months ago

Subtract:8a^2+5b^2-6c^2+7 from 3a^2-4b^2-5c^2-6​

Answers

Answered by avitaylor101
17

Answer:

3a² - 4b² - 5c² - 6 - ( 8a² + 5b² - 6c² +7)

= 3a² - 4b² - 5c² - 6 - 8a² - 5b² + 6c² - 7

= -5a² -9b² + c² - 13

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Answered by roshnikosrabe2609
3

Answer:

3a^2-4b^2-5c^2-6-(8a^2+5b^2-6c^2+7)

3a^2-4b^2-5c^2-6-8a^2-5b^2+6c^2-7

-5a^2-9b^2+c^2-13

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