Question

subtract -9x^2-6x-8 from 3x^2-4x-8​

Answer 1

Step-by-step explanation:

$({3x}^{2} - 4x - 8) - ( - 9 {x}^{2} - 6x - 8) \\ = {3x}^{2} - 4x - 8 + 9x {}^{2} + 6x + 8 \\ = {3x}^{2} + {9x}^{2} - 4x + 6x - 8 + 8 \\ = 12 {x}^{2} - 4x + 6x - 8 + 8 \\ = 12x {}^{2} + 2x + 0 \\ = {12x}^{2} + 2x \\ = 2x(6x + 1)$

${:}\longrightarrow$${\underline{\boxed {\sf{2x (6x+1)}}}}$