Question

subtract a^2-b^2 from the sum of a^2+3ab-2b^2 and-3ab+b^2
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Answer 1

Answer:

0

Step-by-step explanation:

आशा करता हूँ कि आपको सहायता मिला होगा।

Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

subtract a^2-b^2 from the sum of a^2+3ab-2b^2 and-3ab+b^2

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

Step by step explanation:

sum :

$= {a}^{2} + 3ab - 2 {b}^{2} + ( - 3ab + {b}^{2} )$

$= {a}^{2} + 3ab - 2 {b}^{2} - 3ab + {b}^{2}$

$= > {a}^{2} - {b}^{2}$

Subtracting first value from this value :

$= > {a}^{2} - {b}^{2} - ( {a}^{2} - {b}^{2} )$

$= > {a}^{2} - {b}^{2} - {a}^{2} + {b}^{2}$

$= 0$

Basis :

• $\bold{+\:-\:=\:-}$
• $\bold{-\:-\:=\:+[But\:signs\:of\:-]}$

Formula :

$\bold{\boxed{ {a}^{2} - {b}^{2} = (a + b)(a - b)}}$