subtract a^3-4a^2+5a-6 from the sum of 3a^3+a^2+1 and a^2-2
Answers
Answered by
1
3a^3+a^2+1 +a^2-2
= 3a^3 +2a^2-1
subtraction
3a^3+2a^2-1-(a^3-4a^2+5a-6)
= 3a^2+2a^2-1-a^3+4a^2-5a+6
= 2a^3+6a^2-5a+5
= 3a^3 +2a^2-1
subtraction
3a^3+2a^2-1-(a^3-4a^2+5a-6)
= 3a^2+2a^2-1-a^3+4a^2-5a+6
= 2a^3+6a^2-5a+5
Similar questions