Question

Subtract a-4b+5c from 10a-3b+2c

Answer 1

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

Step-by-step explanation:

10a-3b+2bc-(a-4b+5bc)

10a- 3b + 2bc - a + 4b - 5bc

10a-a-3b+4b+2bc-5bc

9a+b-3bc