Question

subtract (a-b-c) from (2a-3b+5c)​

Answer 1

Answer:

(a+3b+4c+4a-b+9c-2b+3c-a)-(2a-3b+4c)

=(4a+4c)-(2a-3b+4c)

=4a+4c-2a+3b-4c

=2a+3b

Step-by-step explanation:

Sum of −2a+b−5c and 3a−2b+c

Sum of −2a+b−5c and 3a−2b+c−2a+b−5c+3a−2b+c=a−b−4c

Sum of −2a+b−5c and 3a−2b+c−2a+b−5c+3a−2b+c=a−b−4cSubtracting 3a−2b+4c from a−b−4c

Sum of −2a+b−5c and 3a−2b+c−2a+b−5c+3a−2b+c=a−b−4cSubtracting 3a−2b+4c from a−b−4ca−b−4c−(3a−2b+4c)

Sum of −2a+b−5c and 3a−2b+c−2a+b−5c+3a−2b+c=a−b−4cSubtracting 3a−2b+4c from a−b−4ca−b−4c−(3a−2b+4c)=a−b−4c−3a+2b−4c

Sum of −2a+b−5c and 3a−2b+c−2a+b−5c+3a−2b+c=a−b−4cSubtracting 3a−2b+4c from a−b−4ca−b−4c−(3a−2b+4c)=a−b−4c−3a+2b−4c=−2a+b−8c