Subtract a force of 50 N along east from a force of 50 N along north.
a] 70.7 N along north-east
b] 70.7 N along north-west
c] 67.7 N along north-east
d] 67.7 N along north-west
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Answer:
cae I
next horizontal force is Fsin30
o
a=
mass
Force
=
2
50sin30
o
=12.5m/s
2
case II
next horizontal force =Fsin30
o
a=
mass
Force
=
2
50sin30
o
=12.5m/s
2
Only friction will differ in the two cases
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