Math, asked by vilesh22, 5 months ago

subtract
a) subtract 8xy+3xy+21 from 6xy+9yz+17
b) subtract a³+b³+³-3abc from 7abc-3a³+5b³-c³​

Answers

Answered by oOfRiEnDsHiPoO
1

Answer:

1) \: 6xy + 9yz + 17 - (8xy + 3xy + 21) \\  \\  = 6xy + 9yz + 17 - 8xy - 3xy - 21 \\  \\  = 6xy - 8xy - 3xy + 9yz + 17 - 21 \\  \\  =  - 5xy + 9yz - 4

__________________________^.^

</strong><strong>2</strong><strong>)</strong><strong>\</strong><strong>:</strong><strong>7abc - 3 {a}^{3}  + 5 {b}^{3}  -  {c}^{3}  - ( {a}^{3}  +  {b}^{3}  +  {c}^{3}  - 3abc) \\  \\  = 7abc - 3 {a}^{3}  + 5 {b}^{3}  -  {c}^{3}  -  {a}^{3}  -  {b}^{3}  -  {c}^{3}  + 3abc \\  \\  =  - 3 {a}^{3}  -  {a}^{3}  + 5 {b}^{3}  -  {b}^{3}  -  {c}^{3}  -  {c}^{3}  + 7abc + 3abc \\  \\  =  - 4 {a}^{3}  + 4 {b}^{3}  - 2 {c}^{3}  + 10abc \\  \\  =  - 2(2 {a}^{3}  - 2 {b}^{3}  +  {c}^{3}  - 5abc) \\  \\  = 2 {a}^{3}  - 2 {b}^{3}  +  {c}^{3}  - 5abc

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Answered by Anonymous
0

Answer:

77778+787889+78888/677888

=687+6778+67/99

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