subtract a.x⁶2n²y+4xy²-3y from y³-n³-9xy²-2n²y
with steps
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Answer:
mark me as the brainliest and see the answer in the step by step explaination section.
Step-by-step explanation:
Given cos
−1
(
b
y
)=log(
n
x
)
n
(
b
y
)=cos{nlog(
n
x
)}
y=bcos{nlog(
n
x
)}
Differentiate with respect to x we get
⇒y
1
=−bsin{nlog(
n
x
)}×
x
n
⇒xy
1
=−bnsin{nlog(
n
x
)}
Again differentiate with respect to x we get
⇒xy
2
+y
1
=−bncos{nlog(
n
x
)}×
x
n
⇒x
2
y
2
+xy
1
=−bn
2
cos{nlog(
n
x
)}
Since y=bcos{nlog(
n
x
)}, we get
x
2
y
2
+xy
1
=−n
2
y
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