Subtract a2
+ 2a -3 from 3a2
– 2a +4
Answers
Answer:
hello dear here is your answer hope it helps you have a great day
Step-by-step explanation:
1a² + 2a – 24 = 0
multiply the 1st & 3rd variable= (-24). two numbers that equal -24 when multiplied& 2(middle variable) when added/subtracted= (6 & - 4)
rewrite using the new “middle” terms...
1a² + 6a – 4a – 24 = 0
(1a² + 6a) – (4a – 24) = 0
a(a + 6) – 4(a+6) = 0
RULE- the terms in parenthesis have to match- combine it(once) with outer terms
(a – 4)(a + 6) = 0
a – 4 = 0
add 4 to both sides (opposite of subtraction/negative #)
a – 4 + 4 = 0+4
a = 4
a + 6 = 0
a+6 - 6 = 0- 6
a = -6
solutions: 4, -6
Answer:
Here's the answer: 2a^2 -4a +7
Step-by-step explanation:
3a^2-2a+4 - [a^2+2a-3]
3a^2-2a+4 - a^2 -2a +3
3a^2 -a^2 -2a -2a +4+3
2a^2 -4a +7
Procedure to follow:
1. If you are asked to subtract a from b , this means you have to calculate b-a
2. Write the terms in order
3. Open the bracket and take care of sign, - - =+
4. Write the terms with same coefficients together
5. Then just simply add/subtract and the write the coefficient with it