Subtract a²-2ax+x² from the sum of 3a²-5ax-x² and
-2a²+3ax+4x².
Answers
Answered by
3
Answer:
= (3a² - 5ax - x²) +( -2a² + 3ax + 4x²)
= 3a² - 5ax - x² - 2a² + 3ax + 4x²
= a² - 2ax + 3x²
now
subtracting a² - 2ax + x² from a² - 2ax + 3x²
= (a² - 2ax + 3x²) - ( a² - 2ax + x²)
=a² - 2ax + 3x² - a² + 2ax - x²
= 2x²
Similar questions