Question

Subtract a2+b + 3bc from the sum of 4a2b + 7bc + ac and 4a2b + 2bc.

the answer 2a2-6b2-7c2​

Answer 1

Answer:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

Answer:

2a2-6b2-7c2

Step-by-step explanation:

this is the answer