Question

Subtract a3-3a2 from b3 -3b2​

Answer 1

Answer:

$( {b}^{3} - {3b}^{2} ) - ( {a}^{3} - {3a}^{2} )$

${b}^{3} - {3b}^{2} - {a}^{3} + {3a}^{2}$

$- {a}^{3} + {b}^{3} + {3a}^{2} - {3b}^{2}$

$- {a}^{3} + {b}^{3} + 3( {a}^{2} - {b}^{2} )$

multiply the equation by -1

$( {a}^{3} - {b}^{3}) - 3( {a}^{2} - {b}^{2})$

$(a - b)( {a}^{2} + ab + {b}^{2}) - 3( {a}^{2} - {b}^{2})$

$(a - b)( {a}^{2} + ab + {b}^{2}) - 3(a + b)(a - b)$

a-b will cancel

${a}^{2} + ab + {b}^{2} - 3a - 3b$

Answer 2

Answer:

a²+ab+b²&3a-3b mark me as brilliant