Question

Subtract ab + cd +7ef from the sum of 3ab + 4cd - 3ef and 2 ab-3cd-ef​

Answer 1

Answer :-

First thing to do -

$\pink{\bold{Find \: the \: sum \: of \: 3ab + 4cd - 3ef \: and \: 2ab - 3cd - ef }}$

3ab + 4cd - 3ef + 2ab - 3cd - ef

= (3 + 2)ab + (4 - 3)cd + (-3 - 1)ef

= 5ab + cd - 4ef

Hence, sum of 3ab + 4cd - 3ef and 2ab - 3cd - ef is 5ab + cd - 4ef.

Second thing to do -

$\color{blue}{\bold{Subtract \: ab + cd +7ef \: from \; 5ab + cd - 4ef. }}$

5ab + cd - 4ef

ab + cd + 7ef

-ㅤ -ㅤㅤ -

━━━━━━━━━

4ab ㅤ+ 11ef

━━━━━━━━━

Hence, final answer is $\large{\red{\fbox{\sf{4ab + 11ef}}}}$

‏‏‎

Note :-

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Answer 2

Answer:

First thing to do --

3ab + 4cd - 3ef + 2ab - 3cd - ef

= (3 + 2)ab + (4 - 3)cd + (-3 - 1)ef

= 5ab + cd - 4ef  

Hence, sum of 3ab + 4cd - 3ef and 2ab - 3cd - ef is 5ab + cd - 4ef.  

Second thing to do -  

5ab + cd - 4ef  

ab + cd + 7ef

-ㅤ -ㅤㅤ -

━━━━━━━━━  

4ab ㅤ+ 11ef  

━━━━━━━━━

Hence, final answer is   ‏‏‎  

Note :-

Scroll the screen to left side to side to view the full Answer. ➜

Step-by step explanation:

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