subtract ab+cd+ 7ef from the sum of 3ab +4cd -3ef and 2ab -3cd -ef answer
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Answer:
Step-by-step explanation:
3ab +4cd -3ef + 2ab -3cd -ef
= 5ab +cd -4ef
5ab +cd -4ef - ( ab+cd+ 7ef )
= 5ab +cd -4ef + ab - cd - 7ef
= 6ab - 11ef
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