subtract ab + cd + 7ef from the sum of 8ab + 6cd - 5ef and 2ab - 3cd - ef
Answers
Step-by-step explanation:
hlo mate here's your answer
ab−
ab−2cd+
ab−2cd+2ac+
ab−2cd+2ac+bd
ab−2cd+2ac+bd(ab−
ab−2cd+2ac+bd(ab−2cd+
ab−2cd+2ac+bd(ab−2cd+2ac+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+3bd
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+3bd2ab+ cd− ac− 2bd
ab−2cd+2ac+bd(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)=ab−2ab−2cd−cd+2ac+ac+bd+2bd=−ab−3cd+3ac+3bd2ab+ cd− ac− 2bdi hope its help you mark as brainlist