Subtract b(b²+b−7)+5 from 3b²−8 and find the value of expression obtained for b = -3. Please don't give irrelevant answers and if you do I will report....
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7
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21
Step-by-step explanation:
(3b²-8) - b(b²+b-7)+5
(3b²-8) - (b³-b²-7b)+5
3b²-b²-8+5-b²-7b
2b²-b³+7b-3
As, b= (-3)
2 x (-3)²-(-3)³+7 x -3
2 x 9- (-27)+(-21)-3
18+27-21-3
= 21
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