Question

Subtract b (b2 +b -7) + 5 from 3b2 – 8 and find the value of expression
obtained for b = -3.

Answer 1

answer:

-22

Step-by-step explanation:

[3*-3*2-8] - [-3(-3*2+-3-7)+5]

[-9*2-8] -  [-3(-3*2+-3-7)+5]

[-18-8] -  [-3(-3*2+-3-7)+5]

-36 -  [-3(-3*2+-3-7)+5]

-36 -  [-3(-6+-3-7)+5]

-36 -  [-3(-9-7)+5]

-36 -  [-3-16+5]

-36 - [-19+5]

-36 - [-14]   [ when we will open the brackets -- = + so -14 will become +14]

-36 + 14 [ -+ = - so we will subtract 14 from 36 and add - sign because the        value of negative integer is more than positive integer]

so, the answer is -22

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