Math, asked by sp0760058, 2 months ago

subtract b(b²+b-7)+5 from 3b²-8 and find the value of expression obtained for b=-3​

Answers

Answered by jules8484
0

Step-by-step explanation:

[b(b2+b-7) +5]-[3b2-8]

b3+b2-7b+5-3b+8

b3+b2-10b+13

Answered by Sonypreety123
0

b(b^2+b-7)+5-(3b^2-8)

b^3+b^2-7b+5-3b^2+8

b^2-2b^2-7b+13

when b=-3

(-3)^2-2(-3)^2-7×(-3)+13

9-2×9-7×(-3)+13

9-18+21+13

25 ANS

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