subtract b(b²+b-7)+5 from 3b²-8 and find the value of expression obtained for b=-3
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Step-by-step explanation:
[b(b2+b-7) +5]-[3b2-8]
b3+b2-7b+5-3b+8
b3+b2-10b+13
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b(b^2+b-7)+5-(3b^2-8)
b^3+b^2-7b+5-3b^2+8
b^2-2b^2-7b+13
when b=-3
(-3)^2-2(-3)^2-7×(-3)+13
9-2×9-7×(-3)+13
9-18+21+13
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