subtract b(b²+b-7)+5 from 3b²-8 and find the value of expression obtained for b=-3.
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3b^2-8-b(b^2+b-7)+5
=3b^2-8-b^3-b^2+7b+5
=-b^3-2b^2+7b-3
for b=-3
-(-3)^3-2(-3)^2+7*(-3)-3
=27-18-21-3
=(-15)
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