Question

Subtract:-


i). 4a – 7ab + 3b + 12 from 12a
​

Answer 1

Answer:

subtract 4a−7ab+3b+12 from 12a−9ab+5b−3

=12a−9ab+5b−3−(4a−7ab+3b+12)

=12a−9ab+5b−3−4a+7ab−3b−12

=8a−2ab+2b−15

Answer 2

subtract 4a−7ab+3b+12 from 12a−9ab+5b−3

=12a−9ab+5b−3−(4a−7ab+3b+12)

=12a−9ab+5b−3−4a+7ab−3b−12

=8a−2ab+2b−15