Math, asked by Vegeta49, 1 day ago

Subtract: (i) -5y2 from y2
(ii) 6xy from -12xy
(iii) (a – b) from (a + b)
(iv) a(b – 5) from b(5 – a)

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Answers

Answered by TheNoobOne
5

Answer:

(i) -5y2 from y2
= y2 – (-5y2) = y2 + 5y2
= 6y2 which is required

(ii) 6ry from -12ry
= -12xy – 6xy
= -18xy which is required

(iii) (a – b) from (a + b)
= (a + b) – (a – b)
= a + b – a + b
= 2b which is required

(iv) a(b – 5) from b(5 – a)
= b(5 – a) – a(b – 5)
= 5b – ab – ab + 5a
= 5a – 2ab + 5b
= 5a + 5b – 2ab which is required.

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