Math, asked by Deepakkr178, 4 months ago

subtract:

i) ab/7-35/bc+6/5ac from 3/5bc-4/5ac.

Answers

Answered by mail2medhaaranis

0

Answer:

525a^2bc^3 - 1750ab^2c^3 - 125a^3b^3c^4 + 6125abc^2 / 875a^2b^2c^4

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