Question

subtract -p+6q-r from the sum of 3p-4q+4r and 2p+3q-8r​

Answer 1

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Answer 2

Answer:

After subtracting −6p+q+3r+8 from p−2q−5r−8 we get,

After subtracting −6p+q+3r+8 from p−2q−5r−8 we get,p−2q−5r−8−(−6p+q+3r+8)

After subtracting −6p+q+3r+8 from p−2q−5r−8 we get,p−2q−5r−8−(−6p+q+3r+8)=p−2q−5r−8+6p−q−3r−8

After subtracting −6p+q+3r+8 from p−2q−5r−8 we get,p−2q−5r−8−(−6p+q+3r+8)=p−2q−5r−8+6p−q−3r−8=7p−3q−8r−16

Step-by-step explanation:

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