Math, asked by plshelp25, 1 year ago

Subtract

p⁴+ 3p³ + 2p²+ p +3 from
Зp⁴- Зр² + P+6​

Answers

Answered by khalidnibras007
1

Answer:

The Answer is 2p^4 - 5p^2 +3-3p^3

Answered by Panzer786
2

Step-by-step explanation:

Hi,

Question : Subtract P⁴ + 3P³ + 2P² + P + 3 From 3P⁴ - 3P² + P + 6.

Answer : 3P⁴ - 3P² + P + 6 - ( P⁴ + 3P³ + 2P² + P + 3 ).

=> 3P⁴ - 3P² + P + 6 - P⁴ - 3P³ - 2P² + P -3

=> 3P⁴ - P⁴ - 3P³ - 3P² - 2P² + P + P + 6 -3

=> 2P⁴ - 3P³ - 5P² + 2P + 3 [ Answer ]

Hence, When we subtract P⁴ + 3P³ + 2P² + P + 3 from 3P⁴ - 3P² + P + 6 , we will get 2P⁴ - 3P³ - 5P² + 2P + 3.

Hope it will help you :)

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