Question

subtract
pls answer correctly​

Answer 1

Answer:

28(t^2)y

Step-by-step explanation:

$13 {t}^{2} y = 13y {t}^{2} \\ \\ therefore \\ 13y {t}^{2} - ( - 15 {t}^{2} y) \\ = 13y {t}^{2} + 15y {t}^{2} \\ = 28y {t}^{2}$

Answer 2

therefore ,

$13y {t}^{2} - ( - 15y{t}^{2})$

Minus sign x Minus sign make + sign

so,

$13y{t}^{2} + 15y{t}^{2} = 28y{t}^{2}$