Question

subtract rhe sum of 3 1/9 and 4 1/6 from the sum of 6 2/5 and 7 1/10. ​

Answer 1

Answer:

First term

$\sf \: 3 \frac{1}{9} + 4 \frac{1}{6} = \frac{28}{9} + \frac{25}{6} = \frac{28 \times 2 + 25 \times 3}{18}$

$\sf \: = \frac{56 + 75}{18} = \frac{131}{18}$

Second Term

$\sf \: 6 \frac{2}{5} + 7 \frac{1}{10} = \frac{32}{5} + \frac{71}{10} = \frac{64 + 71}{10}$

$\sf \: = \frac{135}{10}$

Substract second to first

$\sf \: = \frac{135}{10} - \frac{131}{18}$

$\sf \: = \frac{135 \times 9 - 131 \times 5}{90}$

$\sf \: \frac{1215 - 655}{90}$

$\sf \: = \frac{560}{90} = \frac{56}{9} = 6 \frac{2}{9}$

Answer 2

Answer:

28/9+25/6

36+75/18

111/18

Now, add 32/5+71/10

64+71/10

134/14

Now, subtract 111/18 from 134/14

134/14-111/18

1206-777/126

429/126

143/42

Step-by-step explanation:

Hope it's help you with the answer